Weird Error loading file from path

Scripting Issues
1

This one is weird because I am using the same code somewhere else and it works:

def load_pkl_to_data(mcdb):
	print "mcdb ->", mcdb, type(mcdb)
	mcdbfile = open(getModelPath().findFile("assets/mcscripts/%s.pkl" % mcdb), "r")

load_pkl_to_data(mced)

Which gets me:

mcdb -> mcdbships <type 'str'>

mcdbfile = open(getModelPath().findFile("assets/mcscripts/%s.pkl" % str(mcdb)), "r")
TypeError: coercing to Unicode: need string or buffer, libpandaexpress.Filename found

Anybody got an idea whats going on here?

2

That’s strange all right, but perhaps it would be easier to see where the problem is if you didn’t cram so many operations into a single line. Rewrite it like this:

pathstr = "assets/mcscripts/%s.pkl" % mcdb
modelPath = getModelPath()
filename = modelPath.findFile(pathstr)
mcdbfile = open(filename, "r")

And then when Python gives you the exception, you can see which part of all that it’s actually complaining about.

David

3

Looks like findFile is returning a panda “Filename”, which is not being accepted by the python open function. You might be able to put a str() around the Filename returned by findFile.

Something like this:

def load_pkl_to_data(mcdb):
   print "mcdb ->", mcdb, type(mcdb)
   file_to_find = "assets/mcscripts/%s.pkl" % mcdb
   filepath = getModelPath().findFile(file_to_find)
   mcdbfile = open(str(filepath), "r")

load_pkl_to_data(mced)
4

Actually, you would need to use filename.toOsSpecific() to make it into a string the open() would accept. Or, you could just put “from direct.stdpy.file import open” at the top of your file; the stdpy version of open() will accept a Filename directly (as well as a string).

David