Reposition NodePath to its Bounding volume center?

General Discussion
1

I used to know how to “re-center” a NodePath like this by getting its “tight bounds” but I have forgotten how to code that. Checking the API now, getBound() returns a BoundingSphere which is less useful here.
So how can it be done?

2

Возможно решение. Draw a 2D bounding box around a randomly placed 3D model

3 
min, max = np.getTightBounds()
center = (min + max) * 0.5
np.setPos(np.getPos() - center)

The bounding sphere can also be used. It has a center point you can query. It will be faster than getting the tight bounds.

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