Diameter of an Instance?

Scripting Issues
1

Is there a Panda function/method for returning the overall diameter of an object/actor?

I need an overall diameter calculation based on the object/actor’s tight bounds.

2

You should be able to calculate the width, height and depth of the tight bounds by subtracting the x-, z- and y- components of the max- and min- points provided by calcTightBounds, I believe. Something like this:

# Presume that the NodePath in question is called "myNP"

minPt = Point3()
maxPt = Point3()

myNP.calcTightBounds(minPt, maxPt)

width = abs(maxPt.x - minPt.x)

As I understand it, an object’s “tight bounds” are represented by a box, so it doesn’t really have a diameter; if you are confident that your object is spherical, however, then the width, height or depth, as described above, should at the least approximate the sphere’s diameter.

[edit]
If, on the other hand, you want the diameter of a sphere that passes through the corners of the tight-bounds box, then the following might work – I haven’t checked for any issues that it might miss, I’m afraid:

# Presume that the NodePath in question is called "myNP"

minPt = Point3()
maxPt = Point3()

myNP.calcTightBounds(minPt, maxPt)

diff = maxPt - minPt

diameter = diff.length()